Let the cost of one sheep and one cow be x and y respectively.
Therefore,
5x+5y=129
10x+17y =177
Solving the two equations,
Multiply the first equation by 2 and subtract the second from the results;
10x+10y = 258
10x+17y = 177
0x-7y = 81 => y= $-11.57 (cannot be a negative value). The details of the question need to be checked.
Now,
5x+5y = 129 => 5x-57.86 =129=>5x = 186.86 => x= $37.37
Answer:
Domain All real x.
Range f(x) >= 1.
Step-by-step explanation:
The domain is all real numbers.
|x| is always positive.
At x = 0:
f(x) = |0| + cos 0
= 1 which is the minimum value.
I hope this helps you
f(x)=x-12
X=f(x)+12
f^-1(x)=x+12
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
