Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(11,4)(10,5)
d = sqrt (10 - 11)^2 + (5 - 4)^2
d = sqrt (-1^2) + (1^2)
d = sqrt (1 + 1)
d = sqrt 2
d = 1.41 <===
Hello My Dear Friend!
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We move all terms to the left:</span>

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We add all the numbers together, and all the variables</span>

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We move all terms containing y to the left, all other terms to the right</span>


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Answer:
f(x) = 2(x -3)² +5 or f(x) = 2x² -12x +23
Step-by-step explanation:
The equation of a quadratic is easily written in vertex form when the coordinates of the vertex are given. Here, the point one horizontal unit from the vertex is 2 vertical units higher, indicating the vertical scale factor is +2.
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<h3>vertex form</h3>
The vertex form equation for a parabola is ...
f(x) = a(x -h)² +k . . . . . . vertex (h, k); vertical scale factor 'a'
<h3>equation</h3>
For vertex (h, k) = (3, 5) and vertical scale factor a=2, the vertex form equation of the parabola is ...
f(x) = 2(x -3)² +5 . . . . . vertex form equation
Expanded to standard form, this is ...
f(x) = 2(x² -6x +9) +5
f(x) = 2x² -12x +23 . . . . . standard form equation
Q = -p + 17
or
p = -q + 17
Not sure if this is correct