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Bingel [31]
3 years ago
13

In learning information security, it is important to understand that threats to your company's information assets are present 24

/7 and that there is never a time when a threat is not present. Take a look at the following categories of threats. You are in charge of a team that must deal with the below lists of threats. What prevention methods will your team implement to handle the threats? Please explain the reasons for your decisions.1. Acts of human error
2. Software threats
3. Deviations in services
4. Hardware failures or errors
5. Software failures or errors
Computers and Technology
1 answer:
coldgirl [10]3 years ago
8 0

1. Acts of human error

<u>Explanation:</u>

Insecurity their are many threats that make a desktop or workstation or laptop.  Normally end users have to update operating systems and virus signature updates by periodic scheduling task moreover to avoid threats end-user also have to do periodic scheduling scanning. And the virus cleaning. Download the third-party malware and spyware and then the cleaning process.

End-users have made sure all required service is activated and running in the organization.

The team has to make sure any software threats are found in PC or workstation or laptop or desktop or LAN and try to remove make system up running without any threats.

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<u>C++ program that can be used to determine grades at the end of the semester</u>

#include <bits/stdc++.h>

using namespace std;

void func() //Defining function

{

   int m;

  double stu[60][10];

  cout<<"Enter number of students\n"; //taking input

  cin>>m;

  for(int i=0;i<m;i++)

  {

      cout<<"Enter Student Number: ";

      cin>>stu[i][0];

      cout<<"Enter the four grades of student "<<stu[i][0]<<endl;

      cin>>stu[i][1];

      cin>>stu[i][2];

      cin>>stu[i][3];

      cin>>stu[i][4];

  }

 

  //Calculating first grade average and second grade average

  for(int i=0;i<m;i++)

  {

      stu[i][5] = (stu[i][1] + stu[i][2] + stu[i][3] + stu[i][4])/4;

      stu[i][6] = (0.3*stu[i][1] + 0.2*stu[i][2] + 0.2*stu[i][3] + 0.3*stu[i][4]);

  }

  double sumFAvg=0,sumSAvg=0;

  double classFAvg,classSAvg;

  //Calculating average of first and second grades

  for(int i=0;i<m;i++)

  {

      sumFAvg = sumFAvg + stu[i][5];

      sumSAvg = sumSAvg + stu[i][6];          

  }

  classFAvg = sumFAvg/m;

  classSAvg = sumSAvg/m;

   cout<<"-----------Class Info ------------------\n";

  cout<<"StudentID   Grade1 Grade2 Grad3 Grad4 FirstGrade SecondGrade\n";

  for(int i=0;i<m;i++)

  {

      cout<<stu[i][0]<<"\t\t"<<stu[i][1]<<"\t"<<stu[i][2]<<"\t"<<stu[i][3]<<"\t"<<stu[i][4]

      <<"\t"<<stu[i][5]<<"\t"<<stu[i][6]<<endl;

  }

   cout<<"Class First Grade Average: "<<classFAvg<<endl;   //printing output

  cout<<"Class Second Grade Average: "<<classSAvg<<endl;  

 

}

int main() //driver function

{  double sumFAvg=0,sumSAvg=0;

  double classFAvg,classSAvg;

   int m;

  double stu[60][10];

   func(); //calling function

  return 0;

}

<u>Output</u>

Enter number of students 3

Enter Student Number:1 Enter the four grades of student 1-  50 60 70 80

Enter Student Number:2 Enter the four grades of student 2 -30 4 50 6

Enter Student Number:3 Enter the four grades of student 3 - 10 2 30 40

-----------Class Info ------------------

StudentID   Grade1 Grade2 Grad3 Grad4 FirstGrade SecondGrade

1  50 60 70 80 65 65

2  30 4 50 6 22.5 21.6

3  10 2 30 40 20.5 21.4

Class First Grade Average: 36

Class Second Grade Average: 36

4 0
3 years ago
Read 2 more answers
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