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lions [1.4K]
3 years ago
13

Acid rain is produced from CO2, NO????, and SO???? dissolving in atmospheric water molecules. This causes a decrease in the pH o

f water by increasing the H+ concentration. Complete the reaction between sulfur trioxide and water in the formation of acid rain. Include the phase of the acid produced.
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
3 0

Explanation:

When emission of industrial gases like sulfur dioxide, carbon dioxide and nitrogen oxide combine with water then the rain that consists of these acids fall into the atmosphere is known as acid rain.

When these gases combine with water then they result in the formation of an acid that is present in an aqueous phase.

So, when sulfur trioxide combines with water then the reaction will be as follows.

            SO_{3}(g) + H_{2}O(l) \rightarrow H_{2}SO_{4}(aq)

Hence, we can conclude that sulfuric acid is formed when sulfur trioxide gas reacts with water.

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The speed of a wave on a guitar string is 100 m/s, and the frequency is 1,000 Hz. what is the wavelength of the wave?
Ivenika [448]
v=fw (Assume for this example w is wavelength). w=v/f. w=100/1000= 0.1 m. The wavelength is 0.1 meters
5 0
3 years ago
How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

E = k \frac{q}{r^{2} }

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

        k

q =  <u>1250 N/C x 0.205m</u>²

       8.99 x 10⁹ Nm²/C²

q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0
3 years ago
How many molecules are there in 4.00 l of oxygen gas at 500.∘ c and 50.0 torr?
Oliga [24]
From  the  ideal  gas law   
pv=nRT , n  is  therefore PV/RT
R is  the
R is  gas  constant =62.364 torr/mol/k
P=500torr
 V=4.00l
T=500+273=773k
n={(500 torr x 4.00l)/(62.364 x773k)}=0.041moles
the  number  of  molecules=moles  x avorgadro costant that is  6.022x10^23)
6.022 x 10^23)  x0.041=2.469 x10^22molecules
3 0
3 years ago
A student sets up the following equation to convert a measurement.
Sholpan [36]

Answer:

–0.13 Pa.m²

Explanation:

From the question given above, the following data were obtained:

Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²

Measurement (Pa.m²) =?

We can convert from Pa.mm² to Pa.m² by doing the following:

1 Pa.mm² = 1×10¯⁶ Pa.m²

Therefore,

–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²

–1.3×10⁵ Pa.mm² = –0.13 Pa.m²

Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².

6 0
3 years ago
I watched a scary movie last weekend and now im scared to go into the basement . I dont think i wanna watch scary movies anymore
Levart [38]
I don’t understand your question can you re type it
4 0
3 years ago
Read 2 more answers
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