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3 years ago

A formula for a cough syrup contains 60 mg of codeine per fluid ounce. How many mg are contained in one teaspoonful?

Chemistry

1 answer:

Kruka [31]3 years ago

7 0

Answer : The amount of codeine in one teaspoonful is, 30 mg

Explanation : Given,

Amount of codeine per fluid ounce = 60 mg

Now we have to determine the amount of codeine present in one teaspoonful.

As we know that:

1 teaspoonful = 0.5 fluid ounce

As, the amount of codeine per fluid ounce = 60 mg

So, the amount of codeine 0.5 fluid ounce = $\frac{0.5}{1}\times 60mg=30mg$

Thus, the amount of codeine in one teaspoonful is, 30 mg

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If the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10, how much does the pH change:

andreev551 [17]

Answer:

The pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

Explanation:

To solve this problem we use the Henderson-Hasselbach equation:

pH = pKa + log [A⁻]/[HA]

Let's say we have a weak acid whose pKa is 7.0:

pH = 7.0 + log [A⁻]/[HA]

If the [A⁻]/[HA] ratio is 10/1, we're left with:

pH = 7.0 + log (10/1)

pH = 7.0 + 1

pH = 8.0

Now if the ratio is 1/10:

pH = 7.0 + log (1/10)

pH = 7.0 - 1

pH = 6.0

The difference in pH from one case to the other is (8.0-6.0) 2.0.

So the pH changes by 2.0 if the [A-]/[HA] ratio of a base/weak acid mixture changes from 10/1 to 1/10.

Keep in mind that no matter the value of pKa, the answer to this question will be the same.

3 0

3 years ago

What mass of CaCO3 is required to react completely with 0.56 L of HCl?

Lina20 [59]

The balanced equation for the above reaction is as follows;
CaCO₃ + 2HCl ----> CaCl₂ + H₂O + CO₂
stoichiometry of CaCO₃ to HCl is 1:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP.
volume of 22.4 L occupied by 1 mol
therefore 0.56 L occupied by - 0.56 L / 22.4 L/mol = 0.025 mol
number of HCl moles reacted - 0.025 mol
2 mol of HCl reacts with 1 mol of CaCO₃
therefore 0.025 mol reacts with - 0.025/2 = 0.0125 mol
mass of CaCO₃ required - 0.0125 mol x 100 g/mol = 1.25 g
1.25 g of CaCO₃ is required

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3 years ago

Fix the formula for KF2 Write out the full correct formula?

Korvikt [17]

Given :

A chemical compound $KF_2$ .

To Find :

Fix the formula for $KF_2$ and write the full correct formula.

Solution :

We know, Potassium( K ) and Fluorine( F ) both have a valency of 1 i.e potassium can donate one electron and Fluorine can accept one electron only.

So, the chemical formula $KF_2$ is wrong because no element has filled electron.

Therefore, to stabilise the molecule, 1 Potassium atom should make a bond from 1 Fluorine i.e KF ( correct formula ) .

Hence, this is the required solution.

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2 years ago

Which statements below are an appropriate hypothesis in response to this question? Check all that apply. If a substance changes

Nostrana [21]

Answer:

If a substance undergoes a physical change, then it will retain most of its original properties because no new substance is formed.

If a substance undergoes a chemical change, then it will not retain its original properties because a new substance is formed.

Explanation:

So in shorter words its options 2 and 3

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Alex777 [14]

Answer:

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3 years ago