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irinina [24]
3 years ago
7

A formula for a cough syrup contains 60 mg of codeine per fluid ounce. How many mg are contained in one teaspoonful?

Chemistry
1 answer:
Kruka [31]3 years ago
7 0

Answer : The amount of codeine in one teaspoonful is, 30 mg

Explanation : Given,

Amount of codeine per fluid ounce = 60 mg

Now we have to determine the amount of codeine present in one teaspoonful.

As we know that:

1 teaspoonful = 0.5 fluid ounce

As, the amount of codeine per fluid ounce = 60 mg

So, the amount of codeine 0.5 fluid ounce = \frac{0.5}{1}\times 60mg=30mg

Thus, the amount of codeine in one teaspoonful is, 30 mg

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A steel cylinder of oxygen is being store in a room at 25.0 °C under a pressure of 1250 atm. What pressure would be exerted by t
Rudik [331]

Answer:

P₂ = 1312.88 atm

Explanation:

Given data:

Initial temperature = 25°C

Initial pressure = 1250 atm

Final temperature = 40°C

Final pressure = ?

Solution:

Initial temperature = 25°C (25+273.15 = 298.15 K)

Final temperature = 40°C ( 40+273.15 = 313.15 k)

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

1250 atm / 298.15 K = P₂/313.15 K

P₂ = 1250 atm × 313.15 K / 298.15 K

P₂ = 391437.5 atm. K /298.15 K

P₂ = 1312.88 atm

6 0
3 years ago
Draw a diagram (develop a model) that shows what happens when warm water mixes with cold water in the ocean. Use your model to e
Leokris [45]

Ocean currents determine the various directions of wind movement.

<h3>What is ocean current?</h3>

Ocean currents are caused by differences in density as well as the temperature of the moving winds across the ocean. In the ocean, warm water is found at the top while cooler water occurs far below.

Warm ocean currents originate near the equator and move towards the poles. The ocean currents control the direction of winds in an area.

Learn more about ocean currents: brainly.com/question/20823678

7 0
2 years ago
Which is the most polar bond?<br><br> a. H-Se <br> b. P-Br <br> c. N-I <br> d. No right answer.
docker41 [41]

Answer:

The answer to your question is: b. P - Br

Explanation:

Difference of electronegativities from the periodic table. The one with the highest electronegativity will be the most polar.

a.

H =  2.2

Se = 2.55

Electronegativity = 2.55 - 2.2 = 0.35

b.

P = 2.19

Br = 2.96

Electronegativity = 2.96 - 2.19 = 0.77

c.

N = 3.04

I = 2.66

Electronegativity = 3.04 - 2.66 = 0.38

4 0
2 years ago
10 points!! Please give me work with it and I will mark as brainlist.
Georgia [21]

Answer: The molecular formula will be C_2H_4O_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 40.0 g

Mass of O = 53.3 g

Mass of H = 6.66 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.0g}{12g/mole}=3.33moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.66g}{1g/mole}=6.66moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.33}{3.33}=1

For O =\frac{3.33}{3.33}=1

For H = \frac{6.66}{3.33}=2

The ratio of C : O : H = 1: 1: 2

Hence the empirical formula is COH_2

The empirical weight of COH_2 = 1(12)+1(16)+2(1)= 30g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2

The molecular formula will be=2\times CH_2O=C_2H_4O_2

8 0
2 years ago
How many hydrogen atoms would be present in 12 molecules of water (h2o)?<br>3<br>2<br>24<br>12​
GalinKa [24]

Answer:

Two water molecules contain 4 hydrogen atoms and 2 oxygen atoms. A mole of water molecules contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms.

Explanation:

4 0
3 years ago
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