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igomit [66]
3 years ago
14

Why is blood classified as class evidence and not individual evidence?

Chemistry
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer:

Explanation:

Blood type is considered to be class evidence. Although it may not specifically identify the suspect, explain how it still could be useful in helping to investigate a crime. used to rule out a certain suspect. Explain how the product rule can be used to determine whether two blood samples come from the same source.

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using the same balanced equation, what is the number of moles of carbon dioxide produced from 3.750 moles of propane?
kondor19780726 [428]

Answer:

11.25moles of CO2

Explanation:

First, let us generate a balanced equation for the reaction of propane to produce CO2. This reaction called Combustion. It is a reaction in which propane burns in air (O2) to produce CO2 and H20. The equation is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

From the equation,

1mole of C3H8 produced 3moles of CO2.

Therefore, 3.750 moles of C3H8 will produce = 3.750 x 3 = 11.25moles of CO2

5 0
3 years ago
Which of the following pairs of elements could possibly be in the same group? X has a 1+ ion; Y has a 1- ion. X tends to form a
exis [7]
Let's eliminate these one by one.
The first pair would not be the same, as X would most likely be in group IA, and Y would be in group VIIA, because of their tendency to gain and lose electrons.
The second pair would also violate the same rule, but X would most likely be in group IIA, and Y would most likely be in group VIA.
The third pair would not be the same, as X is most likely in group VIIA, and since Y has eight valence electrons, it is most likely a noble gas.
The final pair has X with atomic number 15, making it phosphorous. Phosphorous wants to gain 3 electrons to have a full octet of 8 outer "valence" electrons, and Y would also like to gain 3 electrons. This means it is possible that the final pair would be in the same group.
5 0
4 years ago
Read 2 more answers
Determine the mass density, specific volume and specific weight of a liquid whose
irakobra [83]

the volume is 63 i hope it is

5 0
3 years ago
Three common gaseous compounds of nitrogen and oxygen of different elementary composition are known: (A) laughing gas containing
Ede4ka [16]

Answer:

Please find how these data prove the law of multiple proportions below

Explanation:

The law of multiple proportions was proposed by an English chemist called John Dalton. The law states that when two elements combine and to form more than one compound. The weights/masses of the second element in the two compounds, which combines with a fixed ratio of the first element, is in a simple whole number ratio.

In this question, Nitrogen is said to combine with oxygen to give three different compounds as follows:

A) laughing gas containing 63.65% nitrogen i.e. 0.6365g

This means that the mass of oxygen will be (1-0.6365) = 0.3635g

B) colorless gas containing 46.68% nitrogen i.e. 0.4668g

This means that the mass of oxygen will be 0.5332g

C) brown toxic gas containing 30.45% nitrogen i.e. 0.3045g

This means that the mass of oxygen will be 0.6955g

The ratios of oxygen in the three compounds is therefore:

0.3635: 0.5332: 0.6955

Divide this ratio by the smallest number (0.3635)

0.3635/0.3635 = 1

0.5332/0.3635 = 1.467

0.6955/0.3635 = 1.913

Multiply this ratio by 2, we have:

2: 2.9 : 3.8

Hence, the simple whole number ratio is 2:3:4.

This proves the law of multiple proportions that oxygen is in simple whole number ratio in the three different compounds.

4 0
3 years ago
What is the molar mass of 81.50 g of gas
garik1379 [7]

The molar mass  of gas = 238.29 g/mol

<h3>Further explanation</h3>

Given

mass = 81.5 g

P=1.75 atm

V=4.92 L

T=307 K

Required

molar mass

Solution

The gas equation can be written  

\large{\boxed{\bold{PV=nRT}}

\tt n=\dfrac{mass}{molar~mass}

So the equation becomes :

\tt Molar~mass=\dfrac{mRT}{PV}

Input the value :

\tt M=\dfrac{81.5\times 0.082\times 307}{1.75\times 4.92}\\\\M=238.29~g/mol

5 0
3 years ago
Read 2 more answers
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