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lianna [129]
3 years ago
10

The attendance at a school concert was 578. Admission was $2.00 for adults and $1.50 for children. The total receipts were $985.

00 (Amount of money they collected from ticket sales). How many adults and how many children attended?
Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

you have 342 children and 236 adults

Step-by-step explanation:

342 X $1.50 = $513 children

236 X $2.00 = $472 adults

$513 + $472 = $985

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Solve the equation
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C. There is no solution.

6(x+4)=5(x-5)+x
6x+24=5x-25+x
6x+24=6x-25
24=-25
The statement is false for any value of x
∴ There is no solution.

Hope my answer helped u :)
7 0
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Simplify (4^7/5^2)^3
Nuetrik [128]

Answer:

4²¹/5⁶ or 4398046511104/15625

Step-by-step explanation:

Remember, when raising a term with an exponent to some power, you must multiply the powers.

(\frac{4^{7} }{5^{2} })^{3} \\\\ = (\frac{(4^{7})^{3} }{(5^{2})^{3} }) \\\\= \frac{4^{7 * 3} }{5^{2* 3} } \\\\= \frac{4^{21} }{5^{6} } \\\\=\frac{4398046511104}{15625}

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3 years ago
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Can someone help me on problem number 8?
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List the coordinates,
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8 0
4 years ago
Find the axis of symmetry and vertex for the parabola y=-4x^2-32x-10
Rom4ik [11]

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4 0
3 years ago
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In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0
3 years ago
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