Answer:
C is correct
Step-by-step explanation:
Given: System of linear inequality
First we will draw the graph of system of equation and then see the correct option.
Equation 1:
We will make the table.
x : -2 0 2
y : 1 0 -1
Test Point: (0,4)
0<-2 ( False )
Shaded area away from (0,4)
Equation 2:
We will make the table.
x : -2 0 2
y : -1 3 7
Test Point: (0,4)
4≥3 ( True )
Shaded area towards (0,4)
Please see attachment for graph.
Hence, C is common shaded area (region)
Answer:
{y≥1
,{y-x>0
Step-by-step explanation:
First of all you have to consider the shaded region. It is bound by two lines.
The first line is a solid line that cuts the y-axis at +1. it's equation is y = 1. since the shade region is on the upper side where y values increase, the unequivocally will be y≥1. notice that the sign ≥ is due to the solid line which indicates points on the solid line are part of the solution.
the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is
y=mx + c where m is gradient and c is the VA)ue of y as the line crosses the y axis ( y-intercept) which in this case is 0 at (0,0).so the equation will be y=1(x) + 0
y=x if we subtract x from both sides we have
y-x=0
since the shaded region is on the upper side as y-x increases the in equality will be
y-x>0 notice since the line is broken it shall be just > not≥ because points on a broken line are not included in the shaded region.
Answer:
Nope. Does not satisfy pythagoras theorem
Step-by-step explanation:
72 squared does nit equal 45 squared plus 56 squared
