When t = 0, S = 2^0 = 1
<span>When t = 2, S = 2^2 = 4 </span>
<span>Change in size = 4 - 1 = 3 cubic mm. </span>
<span>Average rate of change = (S(2) - S(0))/(2-0) = (4-1)/2 = 1.5 cubic mm/month </span>
Answer:
<em>The answer is 200</em>
Step-by-step explanation:
<em>To solve the question given, let us recall the following,</em>
<em>Let r4=200 miles apart</em>
<em>r=50 mph combined speed
</em>
<em>Where </em>
<em>2f+10=50
</em>
<em>2f=40
</em>
<em>f=20
</em>
<em>f+10=30
</em>
<em>or we can express it in another way,</em>
<em>which is</em>
<em>f x4+(f+10)x 4=200
</em>
<em>f x4+f x4+40=200
</em>
<em>8f+40=200</em>
<em>Then</em>
<em>8f is =160
</em>
<em>f=20
</em>
<em>f+10=30
</em>
<em>Therefore,</em>
<em>4x 20+4 x 30=200
</em>
<em>80+120=200
</em>
<em>200=200</em>
<em />
Answer:
are there any answer choices?