Answer:
yes your answer is right
Step-by-step explanation:
<h2>x = 12 in</h2>
Step-by-step explanation:
The diagram depicts a Right-Pyramid with a square base. The height of the pyramid is given as
and the side of the base is given as
.
For any pyramid, the volume is given by the result
![\text{Volume = }\dfrac{1}{3}\times \text{ Area of base }\times \text{ Height}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20%3D%20%7D%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%20%5Ctext%7B%20Area%20of%20base%20%7D%5Ctimes%20%5Ctext%7B%20Height%7D)
So, Volume of given pyramid = ![\dfrac{1}{3}\times (x^{2}\text{ in}^{2}) \times(\dfrac{x}{2} \text{ in})=\dfrac{x^{3}}{6}\text{ in}^{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%20%28x%5E%7B2%7D%5Ctext%7B%20in%7D%5E%7B2%7D%29%20%5Ctimes%28%5Cdfrac%7Bx%7D%7B2%7D%20%5Ctext%7B%20in%7D%29%3D%5Cdfrac%7Bx%5E%7B3%7D%7D%7B6%7D%5Ctext%7B%20in%7D%5E%7B3%7D)
Volume is given as ![288\text{ in}^{3}](https://tex.z-dn.net/?f=288%5Ctext%7B%20in%7D%5E%7B3%7D)
![\dfrac{x^{3}}{6}\text{ = }288\text{ in}^{3}\\\\x^{3}\text{ = }1728\text{ in}^{3}\\x\text{ = }12\text{ in}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E%7B3%7D%7D%7B6%7D%5Ctext%7B%20%3D%20%7D288%5Ctext%7B%20in%7D%5E%7B3%7D%5C%5C%5C%5Cx%5E%7B3%7D%5Ctext%7B%20%3D%20%7D1728%5Ctext%7B%20in%7D%5E%7B3%7D%5C%5Cx%5Ctext%7B%20%3D%20%7D12%5Ctext%7B%20in%7D)
∴ Value of
= ![12\text{ in}](https://tex.z-dn.net/?f=12%5Ctext%7B%20in%7D)
Answer:
FG = 7
Step-by-step explanation:
5x+2+3x-1=9
8x+1=9
8x = 8
x = 1
FG = 5(1)+2 = 7
Answer:
6.75
Step-by-step explanation:
2+10+1+8+12+6+23+5+8+4+4+3+2.59+5.11+5.18+9.07 = 107.95
now we count how much numbers you added up which equals 16 and divide it with 107.95
107.95/16 = 6.746875
now you cant pay half a penny or such and such
so your round it off at 6.746 to 6.75
and there you have it
Answer:
Step-by-step explanation:
You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:
and solving for a:
so
a = 143.0