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s344n2d4d5 [400]
3 years ago
15

Part of the graph of the function f(x) = (x – 1)(x + 7) is shown below. Which statements about the function are true?

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

Answer:

the answers are B,C,D

Step-by-step explanation:

gregori [183]3 years ago
6 0

Answer:

b,c,d

Step-by-step explanation:

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You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
The graph shows a proportional relationship between pounds of aluminum and money earned from recycling.
Aleonysh [2.5K]

Answer: You earn more per pound recycling copper than aluminum.

Step-by-step explanation:

3 0
2 years ago
the manager at a hotel wants to know how often do his costomers rent boats at the nearby lake.Which sampling method will give va
Korvikt [17]

Answer: ❤️Hello!❤️He asks every tenth customer who checks into the hotel. Hope this helps! ↪️ Autumn ↩️

6 0
3 years ago
How many solutions is 8x+47=8(x+5)
expeople1 [14]
8x + 47 = 8x + 40

No solutions  (the above 2 expressions cannot be equal for any value of x)
7 0
3 years ago
Read 2 more answers
Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
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