Answer:
No, similar triangles cannot contain a pair of parallel lines. Yes, because || . Yes, because ∠QUR ≅ ∠TUS (vertical angles) and ∠R ≅ ∠S (alternate interior angles).
Step-by-step explanation:
Answer:
8.27 ft.
Step-by-step explanation:
Using trigonometry of a right angled triangle:
cos 74 = x / 30 where x is the required distance
x = 30 cos 74
= 8.269 ft
Answer:
m and k
Step-by-step explanation:
<span>Without drawing a line on a piece of graph paper. If you know the endpoints of the line segment you can determine the equation of the line and the midpoint of the line. The slope of a perpendicular to a line is the negative reciprocal of the slope of the original line. You can then determine the equation of the perpendicular bisector using the point-slope method. Using a compass and straight edge, you can draw the line. set the compass at the endpoint and wide enough to extend beyond the midpoint. Scribe an arc. Without changing the compass use the other end and scribe another arc so that the two arcs intersect. Connect the two points where the arcs intersect and scribe a line through them. That is the perpendicular bisector.
i found this online ^ hope i helped ^-^</span>
Answer:
I'm going to lay this out in a chart so it's a little easier to see:
F(x) = f(g(x))
x | f (x) | f ' (x) | g (x) | g ' (x)
--------------------------------------
-2 | 8 | 4 |
5 | | 3 | -2 | 6
Remember the chain rule, which says
(f (g (x))) ' = g ' (x) f ' (g (x))
When they ask for F ' (5), they are asking for (f (g (x))) ' when x = 5.
Using the chain rule, that's
F ' (5) = g ' (5) f ' (g (5))
We can simplify using the numbers provided.
F ' (5) = (6) f ' (-2)
F ' (5) = (6) (4)
F ' (5) = 24
I hope that helps!
by jannat <33
