Answer:
Megan would save $19.90.
Step-by-step explanation:
49.75 divided by 0.40 is equal to 19.90.
Answer:
1. The car is slowing down at a rate of 2.5mph/s
2. The greatest acceleration is 10 mph/s.
3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.
Step-by-step explanation:
1. The deceleration of the car is from 16 seconds to 24 seconds is the slope
of the graph from 16 to 24:

the negative sign indicates that it is deceleration.
2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.
From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope
:

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.
The speed of the automobile in that interval, as we see from the graph, is 25 mph.
15 min is 1/4 of an hour so it can run 44x 1/4 or 44/4 =11miles in 15 min
You can solve this analytically to get
.. 55000*(1 +x/100)^10 = 108193
.. (1 +x/100)^10 = 108193/55000
.. 1 +x/100 = (108193/55000)^(1/10)
.. x = 100*((108193/55000)^(1/10) -1) ≈ 7.00
but I find it just as fast to have a graphing calculator do it.
The city's population is increasing 7% per year.
Answer:
Step-by-step explanation:
1a. 25/50 =x/100
25*100= 2500/50= 50
A= 50%
1b. 35/40 = x/100
35*100= 3500/40= 87.5
A=87.5%
2a. 15/20= x/100
20*5= 100; 15*5= 75
A=75%
2b. 25/70= x/100
25*100= 2500/70= 35.71
A=35.71
3a. 15/80= x/100
15*100= 1500/80=18.75
A=18.75%
3b. 30/60= x/100
30/60= 1/2;1/2=0.5;0.5= 50%
A=50%
4a. 70/80 =x/100
70*100=7000/80 =87.5
A=87.5
4b.30/60 = 50% ( same as question #3b)