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2 years ago

Carl plans to invest $500 at 8.25% interest, compounded continuously. How long will it take the money to triple?

Mathematics

1 answer:

gogolik [260]2 years ago

8 0

Use exponential growth equation.

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Need help :)<br><br><br><br> pleaseeeeeee :(

gayaneshka [121]

Answer: $x\geq 88$

This means that he has to save at least $88 or more to have enough money.

Step-by-step explanation:

He has $37 and he needs to save more (+) but we don't know how much more that is, so that's why that is our unknown value. (x). The sum of them has to be at least 125 or greater.

$37+x\geq 125$

Subtract 37

$x\geq125-37$

$x\geq 88$

8 0

3 years ago

Find the limit as x approaches infinity of y=arccos(1+x21+2x2)y=arccos((1+x^2)/(1+2x^2))?

Katyanochek1 [597]

If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x approach infinity
lim y = arccos 1/2 = 1.047

6 0

3 years ago

Me.stewart teaches three science classes her students are freshman and sophomores her student data are shown in relative frequen

almond37 [142]

Answer:

the answer is that D is false

Step-by-step explanation:

the relative frequency chart shows that 0.35 of her total freshman and sophomores take biology (Bottom left corner of the chart).

4 0

2 years ago

Read 2 more answers

Place the samples in order from the sample with the greatest variation to the sample with the least variation.

yulyashka [42]

60 women, 45 women, 20 women, 5women ,

7 0

2 years ago

Read 2 more answers

A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f

Vitek1552 [10]

Answer:

$P(X\cap Y\cap Z)=0.05$

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert $P(X)=0.28$

Percentage of audience in second concert $P(Y)=0.42$

Percentage of audience in third concert $P(Z)=0.30$

Audience Percentage at at-least one concert $P(X \cup Y \cup Z)=0.80$

Percentage of audience at first & second concert $P(X \cap Y)=0.10$

Percentage of audience in first & third concert $P(X \cap Z)=0.08$

Percentage of audience in second & third concert $P(Y\cap Z)=0.07$

Generally the equation for probability of attending all concerts $P(X\cap Y\cap Z)$ is mathematically given by

$P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)$

$P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)$

$P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70$

$P(X\cap Y\cap Z)=0.05$

Therefore the probability that a randomly selected audient attended all the concerts

$P(X\cap Y\cap Z)=0.05$

8 0

3 years ago