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natta225 [31]
3 years ago
10

Which of the following expressions is equivalent to -3(-x+12)?

Mathematics
2 answers:
Mumz [18]3 years ago
5 0
-3(-x + 12).....distribute the -3 thru the parenthesis
3x - 36 <==
iragen [17]3 years ago
4 0
The answer would be 3x+36
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The term in that equation is 3x 7x and -9 hope this helps
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Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1
ElenaW [278]
<h2>Hello!</h2>

The answers are:

A.

\frac{5}{6} and \frac{10}{12}

D.

\frac{6}{7} and 1\frac{5}{7}

<h2>Why?</h2>

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

\frac{5}{6} and \frac{10}{12}

We have that:

\frac{10}{12}=\frac{5}{6}

So, we have that the pairs of numbers

\frac{5}{6}

and

\frac{5}{6}

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

\frac{6}{7} and 1\frac{5}{7}

We have that:

1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}

So, we have that the pair of numbers

\frac{6}{7}

and

\frac{12}{7}

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

\frac{3}{2},\frac{2}{3}

and

3\frac{1}{2},4\frac{4}{4}

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

A.

\frac{5}{6} and \frac{10}{12}

D.

\frac{6}{7} and 1\frac{5}{7}

Have a nice day!

3 0
3 years ago
125% is equivalent to what number​
babymother [125]

125 is equivalent to

<em>1.25</em>

<em>1 1/4 </em>

<em></em>

Pick either one... 1.25 is more likely to be correct

<em></em>

<em></em>

6 0
3 years ago
If i had 12$ but I spent 2 how much would I have left​
Ad libitum [116K]

The answer for this question would be 10

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