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eduard
3 years ago
11

Which could be the function graphed below?

Mathematics
1 answer:
ss7ja [257]3 years ago
5 0

Answer:

sqrt(x+4)

Step-by-step explanation:

the graph is sqrt(x) translated 4 to the left, so +4

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Help???!!??????!??!!???!????!??
svet-max [94.6K]
x_{vertex}= \frac{-2}{2 \cdot 3}=- \frac{2}{6}=  - \frac{1}{3} \\\\\\ 
y_{vertex}=3 \cdot \left(- \frac{1}{3} \right)^2+2 \cdot \left(- \frac{1}{3} \right)+1=3 \cdot\frac{1}{9} -  \frac{2}{3} +1=\frac{1}{3} -  \frac{2}{3} +1= \frac{2}{3}  \\  \\  \\ \boxed {\text {Answer:} \ \left(- \frac{1}{3};  \frac{2}{3} \right)}
6 0
3 years ago
True or False: The following relation is a function.
AysviL [449]

Answer:

A

Step-by-step explanation:

true

6 0
3 years ago
Read 2 more answers
The diagram shows a right-angled triangle.
Alexus [3.1K]

Step-by-step explanation:

there is no diagram so I'm just going to guess this however

sin x = 6/9

sin x = 2/3

sin x = 0.67

x = sin inverse of 0.67

x = 42.1

8 0
3 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 


This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
3 years ago
Answers? I have no clue what to do
zysi [14]
#2 is answer 4, #3 is answer 3, #4 is answer 4. The answer to #5 is 6xy if it is a possibility.
3 0
3 years ago
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