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MatroZZZ [7]
3 years ago
14

Label the na and cl as either + or -. and label each as either cation or anion

Chemistry
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

Na⁺ Cl⁻

Explanation:

Sodium form cation by losing one electron and chlorine form anion by accepting one electron. Both form ionic compound sodium chloride.

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.

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Determine the rate law and the value of k for the following reaction using the data provided.NO2(g) + O3(g) → NO3(g) + O2(g)[NO2
Anton [14]

Answer:

Rate = 43 M⁻¹s⁻¹[NO₂][O₃]

Explanation:

We need to find the reaction order in

rate = (NO₂ )ᵃ (O₃ )ᵇ

given:

( NO₂ ) M                ( O₃ )   M         Rate  M/s

  0.10                        0.33                1.420                (1)

  0.10                        0.66               2.840                (2)

  0.25                       0.66                7.10                   (3)

When keeping the NO₂ concentration constant in the first two while  doubling the concentration of O₃ , the rate doubles. Therefore it is first order with respect to O₃

Comparing (2) and (3) increasing   the concentration of NO₂ by a factor of 2.5  and  keeping  O₃ constant  , increased the rate by  a factor of 2.5. Therefore the rate is first order with respect to NO₂

Then rate law is

= k (NO₂) (O₃ )

To find k take any of the three and substitute the values to find k:

1.420 M/s = k (0.10)M x (0.33)M ⇒ k = 43 /Ms

Then the answer is Rate = 43 M⁻¹s⁻¹[NO₂][O₃]

6 0
4 years ago
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