Ask question

Ask question

All categories

3 years ago

6

What is the specific heat capacity of the metal? use sig figs here. Make sure to choose the correct initial temperature and sole

for -q of metal. *

1 answer:

enot [183]3 years ago

6 0

That should be it... the mass used in tge equation should ALWys be the one of the surrounding

You might be interested in

The following data were measured for the reaction BF3(g)+NH3(g)→F3BNH3(g): Experiment [BF3](M) [NH3](M) Initial Rate (M/s) 1 0.2

Rama09 [41]

Answer:

$-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}$

Explanation:

The rate law of a chemical reaction is given by

$-r_{A}=k\times[BF_3]^{\alpha}\times[NH_3]^{\beta}$

This law can be written for any experiment, and making the quotient between those expressions the reaction orders can be found

Between experiments 1 and 2

$\frac{-r_{A1}}{{-r}_{A2}}=\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)^\beta$

Then the expression for the calculation of $\beta$

$\beta=\frac{ln\frac{-r_{A1}}{-r_{A2}}}{ln\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)}=\frac{ln\frac{0.2130}{0.1065}}{ln\left(\frac{0.250}{0.125}\right)}$

Resolving

$\beta=1$

Doing the same between experiments 3 and 4 the expression for $\alpha$ is

$\alpha=\frac{ln\frac{-r_{A3}}{-r_{A4}}}{ln\left(\frac{\left[BF_3\right]_3}{\left[BF_3\right]_4}\right)}=\frac{ln\frac{0.0682}{0.1193}}{ln\left(\frac{0.200}{0.350}\right)}$

Resolving

$\alpha=1$

This means that the rate law for this reaction is

$-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}$

5 0

3 years ago

The coriolis effect happen when

Schach [20]

When global winds, ocean currents, and other forces move freely across the earths surface.

3 0

3 years ago

A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c

andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=31.8 +273= 304.8 K

Putting value in the given equation:

$\frac{PV}{RT}$ =n

n= $\frac{4.972 \;atm\; X \;9.583 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 304.8}$

Moles = 1.905 moles

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0

2 years ago

What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K

KATRIN_1 [288]

Answer:

2.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 0.109 mole

Pressure (P) = 0.98 atm

Temperature (T) = 307 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

The volume of the helium gas can be obtained by using the ideal gas equation as follow:

PV = nRT

0.98 × V = 0.109 × 0.0821 × 307

0.98 × V = 2.7473123

Divide both side by 0.98

V = 2.7473123 / 0.98

V = 2.8 L

Thus, the volume of the helium gas is 2.8 L.

6 0

2 years ago

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

forsale [732]

Doesnt the number of carbon atoms stay the same.
Though the weight of carbon in 1.5g is 1.24g.

This is because the RAM of C4 is 48.

The RFM of C4H10 is 58. Therefore, 48/58 is carbon in butane.

48/58 x 1.5 = 1.24g

7 0

3 years ago