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3 years ago

Ax) = x² + 4x + 5 What is the vertex?

Mathematics

1 answer:

kakasveta [241]3 years ago

6 0

Answer:

(-2,1)

Step-by-step explanation:

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What is a cubic polynomial function in standard form with zeros –3, 2, and–3?

levacccp [35]

Answer:

$(x-2)(x+3)(x+3)=0\\$

Step-by-step explanation:

Multiply those together and combine like terms. Then make sure you order the terms in descending powers.

7 0

3 years ago

What is the slope, y-intercept and slope intercept equation to this graph. Plz help

fredd [130]

Answer:

y intercept is 3 and slope is 4/1

Step-by-step explanation:

3 0

3 years ago

Use zero property to solve the equation. F(x)=3x(x+7)-2(x+7)

oksian1 [2.3K]

Answer:

x = -7 or x = 2/3

Step-by-step explanation:

I'm assuming you meant solve for x when f(x) = 0.

f(x) = 3x(x + 7) - 2(x + 7)

0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them

x + 7 = 0 or 3x - 2 = 0 -- Use ZPP

x = -7 or x = 2/3 -- Solve

7 0

3 years ago

Help me with just 27

tankabanditka [31]

Answer:

16/13

Step-by-step explanation:

the error is when it was divided, one of the fractions should be reversed to be multiplied

4 ÷ 13

7. 28

4 × 28 ,like this

7. 13

= 112 ,divide both by 7

= 16

7 0

3 years ago

find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on

enyata [817]

Let $f(x)=\tan^{-1}x$ . Then $f'(x)=\frac1{1+x^2}$ . Note that $f(0)=0$ .

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n$

This means that for $|-x^2|=|x|^2$ , or $-1$ , we have

$\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}$

Integrate the series to get

$f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

$\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}$

6 0

3 years ago