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Ostrovityanka [42]
4 years ago
11

Find the exponential function that satisfies the given conditions:

Mathematics
2 answers:
padilas [110]4 years ago
8 0

Answer:

a = starting amount = 67

r = rate = 0.47% = 0.0047

t = week

swat324 years ago
4 0

<u>Answer-</u>

<em>The exponential function that satisfies the given conditions is f(t)=67(0.9953)^t</em>

<u>Solution-</u>

This can be represented as exponential decreasing function,

f(t)=a(1 - r)^t

Where,

  • a = starting amount = 67
  • r = rate = 0.47% = 0.0047
  • t = week

Putting the values,

\Rightarrow f(t)=67(1 - 0.0047)^t

\Rightarrow f(t)=67(0.9953)^t

Therefore, the exponential function that satisfies the given conditions is

f(t)=67(0.9953)^t

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Divide 112 by the possible answers. If the answer comes out even it is a factor. If it comes out with a decimal it is not a factor:


112 / 2 = 56, so 2 is a factor.

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112 /4 = 28, 4 is a factor.

112 / 6 = 18.66, 6 is not a factor.

112 / 7 = 16, 7 is a factor.

112/8 = 14, 8 is a factor.


The factors are: 2 , 4 ,7 and 8.

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The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v
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Answer:

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by \frac{dV}{dt}

Now,

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The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

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Now,

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Let k be any constant.

So,

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