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Yanka [14]
3 years ago
5

What is 65,321 rounded to the nearest ten thousand?

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

70,000

Step-by-step explanation:

5 always rounds UP to the nearest whole number, therefore, 70,000.

Lana71 [14]3 years ago
5 0

Answer:70,000

Step-by-step explanation:

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Please someone help me
ruslelena [56]

Answer:

r = 0.046212737

Step-by-step explanation:

A = 14,400 (what your investment originally is)

P = 7,200 (what you want your investment to be)

n = 365 (interest is compounded daily)

t = 15 (15 years)

Plug all of these numbers into the equation, then solve for r

14,400 = 7,200(1 + r/365)^365 · 15

Divide 7,200 on both sides --> 2 = (1 + r/365)^365 · 15

365 · 15 = 5475 --> 2 = (1 + r/365)^5475

5475√(2) = 1 + r/365 (root 5475 both sides to cancel out the exponent)

(5475√(2)) - 1 = r/365 (subtract one from both sides)

((5475√(2)) - 1) · 365 = r (multiply both sides by 365 to isolate r)

Type the left side into the calculator to get r --> 0.046212737.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Test Number 2: This test tests how smart the users on the website is<br><br> C=5/9(F−32)
joja [24]

Step-by-step explanation:

c=5/9(f-32) can also be written as c = 5(f - 32)/9.

Multiply each side by 9.

That gives us 9c = 5(f - 32).

Apply distributive rule on the right side.

 

9c = 5f - 160

Add 160 to the left side.

9c + 160 = 5f

Lastly, divide both sides 5.

(9c + 160)/5 = f

4 0
3 years ago
X^2 =11+2 sqrt30 find value of X
Fofino [41]

Answer:

If the question goes like this : x²=11+2

then the value of x will be √13

Step-by-step explanation:

x²=11+2

x²=13

x=√13 ans…

7 0
2 years ago
What is 60 /−3 and how do you solve
SVETLANKA909090 [29]
The answer is -20 and you solve by putting it in the calculator
7 0
2 years ago
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Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .
4vir4ik [10]
10.5, 11, 11.5, 12, 12.5...this is an arithmetic sequence with a common difference of 0.5

an = a1 + (n - 1) * d
n = term to find = 23
a1 = first term = 10.5
d = common difference = 0.5

sub and solve

a(23) = 10.5 + (23 - 1) * 0.5
a(23) = 10.5 + 22 * 0.5
a(23) = 10.5 + 11
a(23) = 21.5 <===
6 0
3 years ago
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