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3 years ago

Solve the exponential equation 1/2^x-5=8^x

1 answer:

7 0

$( \frac{1}{2} ) {}^{x - 5} = 8 {}^{x} \\ 2 {}^{ - x + 5} = 2 {}^{3x} \\ - x + 5 = 3x \\ - 4x = - 5 \\ x = \frac{ - 5}{ - 4} = \frac{5}{4}$

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gavmur [86]

Answer:

x=-1

Step-by-step explanation:

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3 years ago

Read 2 more answers

Which systems of equations intersect at point A in this graph?

abruzzese [7]

Answer:

The point of intersection of the system of equations is:

(x, y) = (-2, 1)

The correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

Step-by-step explanation:

Given the point

A (-2, 1)

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Arrange equation variable for elimination

$\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}$

$y+3x=-5$

$-$

$\underline{y-4x=9}$

$7x=-14$

so the system of equations becomes

$\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}$

Solve 7x = -14 for x

$7x=-14$

Divide both sides by 7

$\frac{7x}{7}=\frac{-14}{7}$

Simplify

$x = -2$

For y - 4x = 9 plug in x = 2

$y-4\left(-2\right)=9$

$y+4\cdot \:2=9$

$y+8=9$

Subtract 8 from both sides

$y+8-8=9-8$

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) = (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

$\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}$

Thus, the second option is correct.

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