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Allisa [31]
3 years ago
15

En el colegio se realizó una campaña para medir el grado de obesidad de la población estudiantil. En la escuela hay 1 430 alumno

s, pero sólo 8 de cada 10 aceptaron pesarse, ¿cuántos alumnos faltaron por pesarse?.
Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer:

1144 o 286

Step-by-step explanation:

Si pregunta por la cantidad de personas que se pesaron, la respuesta es (8/10) * (1430) = 8 * 143 = 1144.

Si desea saber cuántas personas no se pesaron, la respuesta es 1430* (2/10) = 286

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Step-by-step explanation:

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6 0
2 years ago
If FC IS RS 4430 and the BEP in unitsis 89, then contribution margin is ?
Umnica [9.8K]

Answer: RS 49.8

Step-by-step explanation:

Given the following :

Fixed cost = RS 4430

Break even point = 89 units

Recall:

Break even point in units = Fixed cost ÷ contribution margin

Therefore,

Contribution margin equals;

(Fixed cost ÷ break even point in units)

= 4430 / 89

= 49.775280

= RS 49.8

5 0
3 years ago
Consider the graph of the function f(x) = e^x
Aliun [14]

Answer:

The y intercept is positive 1 because that's where the graph crosses the y axis.

5 0
3 years ago
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Given right triangle DEF, what is the value of tan(F)?
LiRa [457]

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Step-by-step explanation:


5 0
3 years ago
4. A horizontal ellipse, centered at the origin has a major axis of 10 units and minor axis of 8 units. Write the
s2008m [1.1K]

Answer:

\frac{x^2}{25} +\frac{y^2}{16} =1

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = 2a

where a is called the semi-major axis.

In this case since the major axis is equal to 10 units:

10=2a

solving for the semi-major axis a :

a=10/2\\a=5

and also the minor axis of an ellipse is represented as:

Minor axis = 2b

where b  is called the semi-minor axis.

Since the minor axis has a length of 8 units:

8=2b

solving for b:

b=8/2\\b=4

Now we can use the equation for an ellipse centered at the origin (0,0):

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

and substituting the values for a and b:

\frac{x^2}{5^2} +\frac{y^2}{4^2} =1

and finall we simplify the expression to get the equation of the ellipse:

\frac{x^2}{25} +\frac{y^2}{16} =1

5 0
2 years ago
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