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zhuklara [117]
3 years ago
11

suppose that the population of deer in a state is 1,500 and is growing 2% each year. Predict the population after 4 years

Mathematics
1 answer:
Neko [114]3 years ago
6 0
1500(1+0.02)^4=1,623.64824
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Afina-wow [57]

Answer:

^3 divided by 512 goes to ^3 divided by 8x8x8

8^2 goes to ^2 divided by 8x8x8

Step-by-step explanation:

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What are the solutions to the equation y² + 16 = 212?
Levart [38]
Y² + 16 = 212 
<span>y</span>² <span>= 196 </span>
<span>y = -14 and 14</span>
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The bookstore at SunTan U had a sale on school t-shirts. Thursday, they sold 52 of the marked down t-shirts for a total of $482.
inysia [295]

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7 0
3 years ago
How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

4 0
3 years ago
Given f(x) = 3x + 1, solve for x when f(x) = 7.
irakobra [83]

Answer:

f(7) = 22 or x =2

Step-by-step explanation:

  1. f(x) = 3x + 1
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<u>Or if the equation meant it like this:</u>

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