Which values for A and B will create infinitely many solutions for this system of equations?

The verticles of a triangle are the points R(3,c),Q(9,2) and R(3c,11) where c is constant. Given that angle PQR is 90

IceJOKER [234]

Answer:

Step-by-step explanation:

Find c if ∠PQR = 90°?

I will ASSUME you mean point P is at (3. c)

slope of PQ is (2 - c) / (9 - 3) = (2 - c) / 6

slope of QR is (11 - 2) / (3c - 9) = 9 / (3c - 9)

perpendicular lines have negative reciprocal slopes.

(2 - c) / 6 = -1(3c - 9)/9

9(2 - c) = -6(3c - 9)

18 - 9c = -18c + 54

9c = 36

c = 4

5 0

2 years ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

DiKsa [7]

Answer:

12

Hope it helps

4 0

2 years ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1 0.1702

28.5 1.0252

28.8 0.5077

29.4 0.0127

29.8 0.0827

30.1 0.3452

30.6 1.1827

----------------------------------------

236.1 3.4088

Mean = 236.1 / 8 = 29.51

$S_{x}=\sqrt{3.4088/(8-1)}=0.6978$

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

$t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861$

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

$t$

Finding in the t distribution table α=0.05 with df=7, we have

$t_{0.05,7}=2.365$

$t>-t_{0.05,7}$ = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0

3 years ago

Sophia buys a certain brand of cereal that costs $5 per box. Yani changes to a super-saving brand of the same size. The equation

koban [17]

$ 0.65 more dollars is the price of a box Sophia's original brand of cereal than the price of a box of the super-saving cereal

Amount saved each month with the change in cereal brand if he buys 5 cereal boxes each month is $ 3.25

Solution:

Given that Sophia buys a certain brand of cereal that costs $5 per box

The equation shows the price, y, as a function of the number of boxes, x, for the new brand:

y = 4.35x

Part A:

New brand, y = 4.35x where y is the price and x is the number of boxes

Original brand, y = 5x since given that cereal that costs $5 per box

If Sophia old cereal preference was $5, and the equation shows that the new cereal preference is $4.35, if I subtract the amount of the new one from the old,

we get , 5 - 4.35 = 0.65

Therefore, $ 0.65 more dollars is the price of a box Sophia's original brand of cereal than the price of a box of the super-saving cereal

Part B:

Given that if he buys 5 cereal boxes, let us calculate price for old and new brand

New brand, y = 4.35x

New brand, y = 4.35(5) = 21.75

Original brand, y = 5x = 5(5) = 25

Amount saved = $ 25 - $ 21.75 = $ 3.25

Thus amount saved each month with the change in cereal brand if he buys 5 cereal boxes each month is $ 3.25

6 0

3 years ago

Solve for Y -2x + Y = 3 I need it broken down in steps

MA_775_DIABLO [31]

Step 1: set up equation
-2x+y=3
Step 2: add 2x to both sides
-2x+y=3
+2x +2x

y=3+2x

Hope this helps :)

4 0

3 years ago

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