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Ghella [55]
2 years ago
13

I need to find the value of x

Mathematics
1 answer:
Masja [62]2 years ago
5 0
For right triangles, tangent is opposite length over adjacent length

tangent of 34 is x over 20 because x is the opposite side and 20 is the adjacent

tan(34) = x / 20
x = 20tan(34)
To three decimal places, a decimal approximation is
x ≈ 13.490
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Answer:

True

Step-by-step explanation:

Parallel lines go straight on forever and ever without intersection

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3 years ago
Does this graph show a function explain how you know
Semenov [28]

The correct option is Option D: Yes, the graph passes the vertical line test.

The function is a relationship between two distinct sets X and set Y which can be many-one or one-one. here set X is called the domain and set Y is called the codomain.

The vertical line test states that

If we draw a straight vertical line( which is also parallel to the y-axis) and it touches the graph at only one point at all locations, then that relation is said to be a function and this relation will be also one-one.

So here in this function shown in the graph.

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3 0
2 years ago
How do you find the equation for the line that is parallel to the line y=2/3x-7 and passes through the point (3,-1)
Debora [2.8K]

parallel lines have the same exact slope hmmm what's the slope of y = 2/3x-7 anyway? well, low and behold, is already in slope-intercept form, therefore

\bf \stackrel{\textit{slope-intercept form}}{y=\stackrel{slope}{\cfrac{2}{3}}x-7}.


so we're really looking for the equation of a line whose slope is 2/3, and runs through 3, -1.


\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})~\hspace{7em} slope =  m\implies \cfrac{2}{3} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=\cfrac{2}{3}(x-3) \\\\\\ y+1=\cfrac{2}{3}x-2\implies y=\cfrac{2}{3}x-3

3 0
3 years ago
Factor completely 9r^3-72r^2
PtichkaEL [24]

Answer:

9r²(r - 8)

Step-by-step explanation:

Step 1: Write expression

9r³ - 72r²

Step 2: Factor out 9

9(r³ - 8r²)

Step 3: Factor out r²

9r²(r - 8)

6 0
3 years ago
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