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3 years ago

3(1/2) in fraction form NO DECIMALL FORM

1 answer:

8 0

First just make the whole number a fraction.
3 in fraction form is 3/1.
Now make it have a common denominator with the fraction 1/2.
Just multiply both the numerator and denominator by 2.
This gives you 6/2
Now add!
6/2 + 1/2 = 7/2
So 3(1/2) = 7/2.
:)

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A triangle has side lengths measuring 2x + 2 ft x + 3 ft, and

Marta_Voda [28]

Answer:

$3x+5 < n < x-1$

Step-by-step explanation:

we know that

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the Triangle Inequality Theorem

1) $(2x+2)+(x+3) > n$

solve for n

$3x+5> n$

Rewrite

$n$

2) $(x+3)+n> 2x+2$

$n> x-1$

therefore

$3x+5 < n < x-1$

5 0

3 years ago

SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as

vovangra [49]

Answer:

a) $P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

$P(Z>1.25)=1-P(Z$

b) $P(400$

$P(-1$

c) $z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(500,100)$

Where $\mu=500$ and $\sigma=100$

We are interested on this probability

$P(X>625)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.25)=1-P(Z$

Part b

We are interested on this probability

$P(400$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(400$

And we can find this probability with this difference:

$P(-1$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1$

Part c

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.8$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.2 of the area on the left and 0.8 of the area on the right it's z=-0.842. On this case P(Z<-0.842)=0.2 and P(Z>-0.842)=0.8

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=500 -0.842*100=415.8$

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.

8 0

3 years ago

Please help! Correct answer only, please! Consider the following information matrices for the price of clothing at a clothing st

ololo11 [35]

Answer: b) Large blue t-shirt & Medium RC jeans

Step-by-step explanation:

The subscript numbers attached to the matrix letter represents the:

ROW, COLUMN

$A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\$

A₁,₃ = 1st row, 3rd column

1st row is Blue, 3rd column is Large

B₃,₂ = 3rd row, 2nd column

3rd row is RC jeans, 2nd column is Medium

A₁,₃ + B₃,₂ = Large blue t-shirt & Medium RC jeans

8 0

3 years ago

Please help on this khan problem i can't word it right so there is attachments for the introductions and options for answers

Gwar [14]

Answer:

Step-by-step explanation:

because it is a outlier we can assume these 2 things:

it influences the mean and median, with the mean being effected more

because we know this, we can now solve the problem

both the median and mean decreased, but the mean decreased more than the median

7 0

3 years ago

Read 2 more answers

45 female signers, 40 male singers, 15 instrumental, what is probability that a set of 3 songs contain 1 male, 1 female, 1 inst.

Fantom [35]

Answer:

5 I think

Step-by-step explanation:

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4 years ago