Question

what are the length and width of a rectangular traffic sign if the length exceeds the width by 24 inches and the perimeter by 128 inches​

Answer 1

Answer:

length = 44 in, width = 20 in

Step-by-step explanation:

$\text{The formula of a perimeter of a rectangle:}\\\\P=2(l+w)\\\\l-length\\w-width\\\\\text{We have}\ l=(w+24)\ in,\ P=128\ in\\\\\text{Substitute:}\\\\128=2(w+24+w)\qquad\text{divide both sides by 2}\\\\64=2w+24\qquad\text{subtract 24 from both sides}\\\\40=2w\qquad\text{divide both sides by 2}\\\\20=w\to w=20\ in\\\\l=20+24=44\ in$