The events A and B are independent if the probability that event A occurs does not affect the probability that event B occurs.
A and B are independent if the equation P(A∩B) = P(A) P(B) holds true.
P(A∩B) is the probability that both event A and B occur.
Conditional probability is the probability of an event given that some other event first occurs.
P(B|A)=P(A∩B)/P(A)
In the case where events<span> A and B are </span>independent<span> the </span>conditional probability<span> of </span>event<span> B given </span>event<span> A is simply the </span>probability<span> of </span>event<span> B, that is P(B).</span>
Statement 1:A and B are independent events because P(A∣B) = P(A) = 0.12. This is true.
Statement 2:<span>A and B are independent events because P(A∣B) = P(A) = 0.25.
This is true.
Statement 3:</span><span>A and B are not independent events because P(A∣B) = 0.12 and P(A) = 0.25.
This is true.
Statement 4:</span><span>A and B are not independent events because P(A∣B) = 0.375 and P(A) = 0.25
This is true.</span>
Answer:
The answer is 6.3
Step-by-step explanation:
The commission is 5% on everything she sells
If she sold $1650.00
First you have to find her commission
100%=1650
5%=x
100•x=1650•5
100•x=8250
—— ———
100 100
x=82.5(this is her commission)
Now you have to add $82.5 to total she earns in the week.
$400.00+ $82.5 = $482.5
The Vanessa’s total pay last week was $482.5
Answer:
L.S = R.S ⇒ Proved down
Step-by-step explanation:
Let us revise some rules in trigonometry
- sin²α + cos²α = 1
- sin2α = 2 sin α cosα
- cscα = 1/sinα
To solve the question let us find the simplest form of the right side and the left side, then show that they are equal
∵ L.S = csc2α + 1
→ By using the 3rd rule above
∴ L.S = 
+ 1
→ Change 1 to 
∴ L.S = +
→ The denominators are equal, then add the numerators
∴ L.S = 
∵ R. S = 
∵ (sinα + cosα)² = sin²α + 2 sinα cosα + cos²α
∴ (sinα + cosα)² = sin²α + cos²α + 2 sinα cosα
→ By using the 1st rule above, equate sin²α + cos²α by 1
∴ (sinα + cosα)² = 1 + 2 sinα cosα
→ By using the 2nd rule above, equate 2 sinα cosα by sin2α
∴ (sinα + cosα)² = 1 + sin2α
→ Substitute it in the R.S above
∴ R. S =
∵ L.S = R.S
∴ csc 2α + 1 =
9514 1404 393
Answer:
mutually exclusive
Step-by-step explanation:
The formula of interest is ...
P(A or B) = P(A) + P(B) - P(A and B)
Filling in the given values, we have ...
9/10 = 2/5 + 1/2 - P(A and B)
Solving for P(A and B), we get ...
P(A and B) = 2/5 +1/2 -9/10 = 4/10 +5/10 -9/10
P(A and B) = 0
__
Events are mutually exclusive when <em>they can never happen at the same time</em>. That is, P(A and B) = 0.
The events A and B are mutually exclusive.
