Answer:
- a(x) = 20 + 0.60x
- domain [0, 50]; range [20, 50]
- maybe
Step-by-step explanation:
a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...
0.40 × (50 -x)
The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...
1.00 × (x)
Then after the remove/replace operation, the total amount of acid in the container is ...
a(x) = 0.40(50 -x) +1.00(x)
a(x) = 20 +0.60x . . . . . liters of acid in the final mixture
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b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)
The associated range is 20 ≤ a ≤ 50. (liters)
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c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.
Answer: 2 Squared is the answer
Step-by-step explanation:
Squared with 8 and 6 imagine 6 parcel and 8 sides.
It minus's to equal the equation 2.
Answer:
30%
Step-by-step explanation:
There's 100 squares in total, and 30 of the 100 are shaded! 30/100 is .3 and multiplied by 100 gives you the percentage, 30.
Answer:
5−4+4=16+4
Step-by-step explanation:
