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Goshia [24]
3 years ago
9

19 in2 17 in2 12 in2 22 in2

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:22in2

Step-by-step explanation:

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What is the x-intercept of the graph that is shown below?
Mice21 [21]

Answer:

3

Step-by-step explanation:

its 3 because the line goes through 3 on x axis of the graph

5 0
3 years ago
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D(-3,4) E(7, 6) 1:3
sesenic [268]

Answer:d

Step-by-step explanation:

4 0
3 years ago
According to a student survey, 16 students liked history, 19 liked English, 18 liked math, 8 liked math and English, 5 liked his
Bogdan [553]
When building a Venn Diagram, I always start from the area with the most overlap to the areas of least overlap. Once you have placed the 3 in the middle, you have counted those people, and therefore you must subtract them from the other surveys. Example: since there are 3 people that like all three subjects, now only have 5 students that like just math and English instead of 8. 

Therefore:
A) 36 Students were in the survey
*Add all the numbers within the Venn diagram up. Overlapping doesn't matter because no one is double counted. 

B) 6 People liked only Math
*Can't touch any other circle but Math

C) 20 Students liked English and math, but not history
*You add 9+5+6, since these bubbles are not overlapping with history. 

I Hope this helps and let me know if you have any further questions!

4 0
3 years ago
Use the Two-Transversal Proportionality Corollary to find the value of x.
Artist 52 [7]
I hope this helps you




12/12+x=13/13+26



12/12+x=13/39



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x=24
5 0
2 years ago
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Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
3 years ago
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