Both of the fractions can be added since they both have 8 as the denominator 3/8+5/8=8/8 which is a whole.
I hope this helps you
42=1.42
42= 2.3.7
42= 6.7
Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>
Answer:
13ft
Step-by-step explanation:
Kindly find attached a rough draft of the situation.
Step one:
Given data
The length of the slide represents the
Hypotenuse of the situation on the rough sketch
Angle =33°
Required
The height of the ladder which is the adjacent of the rough sketch represented by x
Step two:
Applying SOH CAH TOA
Cos θ= adj/hyp
Cos 33=x/15
0.84=x/15
Cross multiplying
x=0.84*15
x=12.6
To the nearest foot the ladder is 13ft tall
