When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.
For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
(1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
= (1/2)*|1 -11 +4| = 3
Answer:
![\sqrt[4]{2}^{3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%5E%7B3%7D)
Step-by-step explanation:
Try 122.
<h3 />
Step-by-step explanation:
Since <em>x</em> = 1, x^6 = 1.
Since <em>y</em> = 11, 11^2 = 121.
1 + 121 = 122.
<h3 /><h3>
So, the value of <em>
x</em>
^ 6 + <em>
y </em>
^ 2 = 122.</h3><h3 />
6 strawberries.
one plum= 32 calories
one strawberry=4 calories
total calories=56
56-32=24
24 calories come from the strawberries
24÷4=6
Therefor 6 strawberries
I hope this helps you
242÷57
4,245