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aniked [119]
3 years ago
6

Which equation has solutions of 6 and -6? x2 – 12x + 36 = 0 x2 + 12x – 36 = 0 x2 + 36 = 0 x2 – 36 = 0

Mathematics
2 answers:
Colt1911 [192]3 years ago
6 0

Answer:

last option

Step-by-step explanation:

Anastasy [175]3 years ago
4 0
X^2 – 12x + 36 = 0
(x-6)(x-6)=0
x=6 x=6
Not a solution

x^2 + 12x – 36 = 0
Doesn't factor
Not a solution

x^2 + 36 = 0
x=√-36
Not a solution

x^2 – 36 = 0
(x-6)(x+6)= 0
x=6 x=-6
Solution


ANSWER: The equation with solutions of x=6 and x=-6 is the last choice: x^2 - 36= 0.

Hope this helps! :)
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77julia77 [94]

Answer:

The first option is correct: Angle 2 through 5

Step-by-step explanation:

Both angles 2 and 5 are directly vertical or opposite to each other and are the only angles that are proportionate/equal sizes.

The other three options are incorrect because angles 4 and 3 are not the same equal value and are right next to each other making them not vertically across.

angles 1 and 5 are close to being vertical but are not the same size as angle 1 is much smaller than angle 5.

angles 6 and 1 are next to each other making them not vertically to each other and angle 6 is much larger than angle 1.

the correct answer is angles 2 and 5, the first option.

8 0
3 years ago
What is the difference between an irrational number and an integer? <br> PLEASE NEED HELP ASAP!!!!
tatiyna
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4 0
3 years ago
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The value of the definite integral / 212x – sin(x) dx / 122x-sin(x) is
blondinia [14]

Hi there!

\boxed{= 70 + cos(12) - cos(2) \approx 71.26}

\int\limits^{12}_{2} {x-sin(x)} \, dx

We can evaluate using the power rule and trig rules:

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Therefore:

\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}

Evaluate:

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3 years ago
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