Answer:
Maria sent 7 messages
Bob sent 5 messages
Ahmad sent 45 messages
Step-by-step explanation:
Given that Maria, Ahmad, and Bob sent a total of 52 text messages during the weekend.
If Maria sent fewer messages than Bob, and Ahmad sent times as many messages as Bob
Since the exact figures were not given, then let make an assumption that Ahmad sent 9 times as many messages as Bob.
If Bob sent 5 messages, then, Ahmad will send 5 × 9 = 45 messages
Also, it is given that Maria sent fewer messages than Bob. Take 45 away from 52. That is,
52 - 45 = 7
Therefore,
Maria sent 7 messages
Bob sent 5 messages
Ahmad sent 45 messages
360 - 20 + 2x = 360
340 + 2x = 360
2x = 20
x = 10
The answer is d as in dog
14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.
To solve this problem, we would write a system of linear equations.
- Let x represent the machine that cost $150
- Let y represent the machine that cost $225
We can proceed to write our equations now.

From equation 1

<h3>The Value of Y</h3>
put equation (iii) into (ii)

<h3>The Value of X</h3>
Since we know the number of y, we can simply substitute it into equation (i) and solve.

From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.
Learn more about system of equations here;
brainly.com/question/13729904