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jekas [21]
3 years ago
8

What is the total weight of the bunches of bananas that weigh 1 3\4 pounds​

Mathematics
1 answer:
Lisa [10]3 years ago
7 0
If it weighs 1 3/4 lb’s then that’s it’s total weight…
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How do I do this I really don't understand anything here
Lera25 [3.4K]

The red arrows show that the lines are parallel, but using the stuff given you can make an equation.
its hard to explain without drawing but starting from the 60 if you can make a Z you will get alternate angles and that mean that the given equation MUST be equal to 60. So,

8x-4=60

8x=60+4

8x=64

x=64/8

x=8 (is your answer)

hope you understand


8 0
4 years ago
The table below shows the number of marbles of different colors in a bag: Marble Experiment Color of Marbles Number of Marbles R
Nesterboy [21]

Answer:

7/14

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A rectangular garden has length twice as great as its width. A second rectangular garden has the same length as the first garden
Slav-nsk [51]
I say 12 because that would mean the first rectangle is 6x12 and the second is 10x12
4 0
4 years ago
The number of people that belong to a certain social website is 412 and growing at a rate of 5% every month. How many members wi
vladimir1956 [14]
Population are always modeled by exponential growth equation given by:
f(x)=a(1+b)^t
where:
a=original number
b=rate of growth
t=time
thus
f(x)=412(1.05)^t
the population after 9 months will be:
f(9)=412(1.05)^9=639.15=639 
3 0
3 years ago
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What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc
Wittaler [7]

We are given equation :x^6+6x^3+5=0

Use\:the\:rational\:root\:theorem

\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5

Therefore, final factored form it

x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.


5 0
4 years ago
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