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Viefleur [7K]
3 years ago
6

A student was given two clear liquids; a colorless liquid and a dark-blue liquid. The student was asked to combine the liquids i

n a beaker and record observations. Which of the following results, if true, would provide the best evidence that a chemical change took place when the liquids were combined?
a) The resulting mixture was cloudy.
b) The total volume of the mixture was equal to the sum of the initial volumes.
c) The resulting liquid was light blue.
d) The liquids formed two separate layers in the beaker.
Chemistry
1 answer:
Anon25 [30]3 years ago
7 0

Answer:

The correct option is;

a) The resulting mixture was cloudy

Explanation:

Here we have the initial color as

1. Colorless and

2. Dark blue

We analyze each of the results as follows

a) The resulting mixture was cloudy

A cloudy mixture forming when the two liquids are mixed is most likely due to the formation of a suspension from  a new substance That is a new compound is formed

b) The total volume of the mixture was equal to the sum of the initial volumes.

Here since there is no change in the physical properties as the volume of the mixture is the sum of the volumes of the  constituent then there is unlikely to be a chemical change

c) The resulting liquid was light blue

Here, the observation is more of a physical change

d) The liquids formed two separate layers in the beaker.

This is an indication that there was no mixing of the liquids hence no reaction or chemical change.

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Answer: \Delta H_{rxn}=-20kJ/mol-(+66kJ/mol)

Explanation:

Heat of reaction or enthalpy change is the energy released or absorbed during the course of the reaction.

It is calculated by subtracting the enthalpy of reactants from the enthalpy of products.

\Delta H=H_{products}-H_{reactants}

\Delta H = enthalpy change = ?

H_{products} = enthalpy of products

H_{reactants} = enthalpy of reactants

For the given reaction :

2NO_2(g)\rightarrow N_2O_4(l)

\Delta H=H_{N_2O_4}-2\times H_{NO_2}

\Delta H=-20kJ/mol-(+66kJ/mol)

6 0
3 years ago
Stock nomenclature nh4no3
dedylja [7]

Answer: Stock nomenclature of NH_4NO_3 is ammonium(I) nitrate

Explanation:

Stock nomenclature is used for chemical nomenclature where the oxidation states of some or all of the elements in a compound are indicated  by Roman numerals in parentheses.

For example:

FeCl_2 which has iron in oxidation state of +2 has stock nomenclature of iron(II) chloride.

FeCl_3 which has iron in oxidation state of +3 has stock nomenclature of iron(III) chloride.

Thus the stock nomenclature of NH_4NO_3 is ammonium(I) nitrate as ammonium has oxidation state of +1.

6 0
3 years ago
In electrophilic aromatic substitution reactions the hydroxyl group is an o p-director because?
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In electrophilic aromatic substitution reactions the hydroxyl group is an o,p-director because: hydroxyl group donates the electron density to the ring by induction and destabilizes the meta sigma complex and  by resonance and it  stabilizes the ortho and para sigma complexes of aromatic ring .

Most ring activators have atoms with unshared electron pairs directly attached to a carbon atom of the benzene ring . For example, the — OH group has two pairs of unshared electrons on the oxygen atom , which will form a bond to a carbon atom of the benzene ring . Thus , the — OH group will be an activating group in electrophilic aromatic substitution reactions .

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2 years ago
What do we call the sugar in<br> sweet tea?<br> A. solute<br> B. solvent<br> C. solution
kow [346]

Answer:

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6 0
3 years ago
Read 2 more answers
According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 N
Gnesinka [82]

<u>Answer:</u> The mass of water produced in the reaction is 47.25 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{29.7g}{17g/mol}=1.75mol

The given chemical reaction follows:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce = \frac{6}{4}\times 1.75=2.625mol of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g

Hence, the mass of water produced in the reaction is 47.25 grams.

3 0
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