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SCORPION-xisa [38]
3 years ago
6

You are given 60 ml of 2.0 m naoh solution. how many ml of 6.0 m hcl solution is needed to completely neutralize the naoh soluti

on? s
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
<span>HCl+NaOH---> NaCl+H2O the 2 reactives are monovalent . the NaOH is 3 times as concentrated as HCl So you need 3 volumes HCl 2M to neutralize 1 volume NaOH 6M and for 75 ml NaOH 6M you need 75*3= 225mL HCl 2M second question HBr+NH4OH--> NH4Br+H2O as before 1 HBr for 1NH4OH is needed IF they have the same molarity Here you need 40/10 =4 more HBr than NaOH The molarity of NaOH is 4*0.5 =2M</span>
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What evidence do you need to determine that two rocks have some similar minerals because the minerals from the original rock was
klio [65]

Answer:

It comes from same parent material.

Explanation:

The two rocks have some similar minerals which indicates that they are comes from the same parent material but with the passage of time it is mixed with other minerals due to which they are some different in composition from one another so we can conclude that they comes from the same parent material due to the presence of some similar minerals.

5 0
3 years ago
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Answer:

Ionic bonding occurs when atoms either gain or lose one or more valence electrons, resulting in the atom having either a negative or positive charge.

Through ionic bonding, an atom of each element will combine with the other to form a molecule, which is more stable since it now has a zero charge.

Explanation:

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3 years ago
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3 years ago
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How many moles are in sample containing 2.71 x 10^24 atoms of iron?
Deffense [45]

Answer:

4.5 moles

Explanation:

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5 0
3 years ago
A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo
Kryger [21]

Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

M₁V₁ = M₂V₂  

0.0952 M * 38.73 mL = M₂* 49.48 mL

M₂ = 0.0745 M

8 0
3 years ago
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