Let's begin by listing out the information given to us:
We start out by observing that Triangles MKR & ACD are similar or proportional

We will solve for the missing side by using the similar triangle theorem. This is shown below:~
-5/2 is the slope of thosr points
Y-intercept: 3
x-intercept: 2
put (0,3) and (2,0) as points on the graph
Answer:
Step-by-step explanation:
Problem A
t(1) = 2(1) + 5
t(2) = 2*2 + 5 = 9
t(3) = 2*3 + 5 = 11
t(4) = 2*4 + 5 = 13
So this is the explicit result. Now try it recursively.
t_3 = t_2 + 2
t_3 = 9 + 2
t_3 = 11 which is just what it should do.
t_n = t_(n - 1) + 2
Problem B
t(1) = 3 * 1/2
t(1) = 3/2
t(2) = 3*(1/2)^2
t(2) = 3 * 1/4
t(2) = 3/4
t(3) = 3*(1/2)^3
t(3) = 3 * 1/8
t(3) = 3/8
t(4) = 3 (1/2)^4
t(4) = 3 (1/16)
t(4) = 3/16
So in general
t_n = t_n-1 * 1/2
For example t(5)
t_5 = t_4 * 1/2
t_5 = 3 /16 * 1/2 = 3/32
18. just subtract 49.6 from 54. 54 - 49.6=4.4 He most lose 4.4 pounds.
19. all you need to do is add 4.6 to 83. 83+4.6=87.6 She will weigh 87.6 pounds
20. divide 910 by 7. 910÷7=130 The dog ate 130 grams per day
21. multiple 4.95 by 5. 4.95×5=24.75 Her total bill was 24.75
22. subtract 12.96 from 20. 20-12.96=7.04 Her change was 7.04