A science fair poster is a rectangle 3 feet long and 2 feet wide. What is the area of the poster in square inches?

change the precent to a fraction 120% (simplify your answer) show work with this and steps on the side

storchak [24]

Here are my steps 11/5= 2 1/5

4 0

3 years ago

Han drinks three gallons of iced tea each day. Each gallon of iced tea contains ¾ cups of sugar. How much sugar does Han drink w

erica [24]

Answer:

3 cups of sugar.

Step-by-step explanation:

Han drinks 3/4 of a cup of sugar each day when she drinks iced tea. She drinks 3 gallons, and each contains 3/4. If each contains only 3/4, we will have to multiply 3/4 by 3 gallons to find our answer to this question.

$\frac{3}{4} = 1 \text{-gallon}$

So, now we will have to multiply 3/4 by the number 3.

$\frac{3}{4}$ × $3$ = $\frac{12}{4}$

12/4 is equal to 3, so the answer is 3.

7 0

2 years ago

Enter the equation of the line in slope-intercept form. The line parallel to y = 7 6 x + 6 that passes through (−6, 0). The equa

Neko [114]

Attached solution with steps.

3 0

3 years ago

4/9 expressed as a percent please help and show work! Please

coldgirl [10]

4/9 as a percent is (about) 44% Work:
First get a decimal by dividing 4/9(4 divided by 9) you get 0.44 repeating
Next, take away the 0. and add a percent sign at the end of 0.44. You get 44%
Truly, the answer is 44.44444...% because the four repeats, but if you round it is simply 44%

7 0

3 years ago

Read 2 more answers

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

2 years ago