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GarryVolchara [31]
3 years ago
8

A science fair poster is a rectangle 3 feet long and 2 feet wide. What is the area of the poster in square inches?

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0
3'=3*12=36"
2'=2*12=24"
Area = 36" * 24" = 864 sq. in.
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If the lengths of two sides of a triangle are 5 and 9, respectively, which of the following could be the length of the third sid
slamgirl [31]

There are two answers:

B) 5

C) 8

==============================================

Explanation:

If we had a triangle with sides a, b and c, then we can say

b-a < c < b+a

where b is larger than 'a'. This is the triangle inequality theorem

In this case, a = 5 and b = 9 so,

b-a < c < b+a

9-5 < c < 9+5

4 < c < 14

Telling us that c is some number between 4 and 14, not including either endpoint. If c is a whole number, then c could be any value from this set: {5,6,7,8,9,10,11,12,13}

We see that the numbers 5 and 8 are in this set. The values 3 and 15 are not in the set.

3 0
3 years ago
SERIOUSLY HELPPPPPPPP
AlekseyPX

9514 1404 393

Answer:

  B.

  • as x increases, f(x) decreases;
  • as x decreases,f(x) decreases

Step-by-step explanation:

The function is of even degree with a negative leading coefficient. f(x) will tend toward negative infinity as x gets larger or smaller. That is ...

  • as x increases, f(x) decreases;
  • as x decreases,f(x) decreases

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<em>Even degree</em> means the end behaviors are the same for both large and small x. <em>Negative leading coefficient</em> means the function value decreases for larger x.

8 0
3 years ago
What is her answer ?
mihalych1998 [28]

Answer:

4

lolz sorry for a late answer bud

Step-by-step explanation:

7 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
Multiply and find the value of x
RUDIKE [14]

Answer:

X=15

Step-by-step explanation:

6 0
2 years ago
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