Answer:
17b
Step-by-step explanation:
8980
80987
78987=
I hope this helps you
123×1000000000
123×10^10
123×1/100×10^12
1,23×10^12
Answer:
208
Step-by-step explanation:
Given that;
Given that;
y= a(1 - b)^t
Where;
wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.
To obtain the constant b,
y= ae^-bt
Substituting values;
1000 = 3000 e^-b(50)
1000/3000 = e^b(50)
0.33 = e^b-(50)
ln (0.33) = ln(e^b(-50))
-1.1 = -50b
b= 1.1/50
b= 0.022
After two hours or 120 minutes;
y= 3000(1 - 0.022)^120
y= 207.8661772
y= 208
Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
