I believe the answer would be the 3rd one
The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:

<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:


Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:


Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
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Translate down and reflect over a vertical line! :)
it means bring the cup down and then flip
Answer:
-11x +3y + 25
Step-by-step explanation:
7-8x+4y+18-3x-y
= -8x-3x +4y-y +18+7 (putting like terms together)
= -11x +3y + 25 (Adding like terms)
If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x approach infinity
lim y = arccos 1/2 = 1.047