(-2,18):(8,38) Set them equal to each other you get, x^2-6x-16=0, you can factor to get, (x-8)(x+2) to get solutions 8,2 for the x values then plug in for y values.
Helen is currently is 8 years old.
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How to solve world problem ?</h3>
Endeavor to understand the question, analyze it and interpret it into equation.
Given that Helen's age is multiples of 4. Next year it'll be a multiple of 3. Helen's older brother is now 19.
This means Helen current age is multiple of 4 and next year it will be a multiple of 3. Also, Helen's age is less than 19
The two available numbers that fit this analysis and less than 19 are 8 and 9. 8 is multiple of 4. 8 + 1 = 9 which is multiple of 3
Therefore, Helen is 8 years old now
Learn more about Arithmetic here: brainly.com/question/6561461
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Step-by-step explanation:
i believe the answer is y=24
I believe this question should be a multiple choice question as there are numerous solutions.
Some of these solutions are:
4/3x+ 4 2/3 = <span>4/3x+ 8/3
</span>4/3x+ 4 2/3 = <span>8/6x+ 4 4/6
</span>4/3x+ 4 2/3 = 12/9x + 4 2/3
This can be explained as:
For 8/6x+ 4 4/6, divide the numerator by 2 and the denominator by 2 in each of the terms, the output will be the original expression.
For 12/9x + 4 2/3 , divide the numerator by 3 and the denominator by 3 in the first term (12/9x), the result will be the original expression.
Answer:
Step-by-step explanation:
Let 
Subbing in:
a = 9, b = -2, c = -7
The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:
Group together in groups of 2:
Now factor out what's common within each set of parenthesis:
We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:
Remember that 
so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.
The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring 
gives us that x = 1 and -1. The other set is a bit more tricky. If
then
and
You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:
±
which will simplify down to
±
Those are the 4 solutions to the quartic equation.
