The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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Answer:
I believe the answer is bigger than.
Step-by-step explanation:
According to the Triangle Midsegment Thereom, if the midsegment of a triangle is parallel to a side of the triangle, then the midsegment is half the length of side it is parallel to, therefore...
45=(7x+13)/2
And after that, you continue to solve the problem using Algebra
90=7x+13
77=7x
11=x
I hope this answer was helpful! :)
Answer:
yes
Step-by-step explanation:
substitute 4 for g. 4x5= 20 and 20 is definitely less than or equal to 25
All we have to do to obtain r is to take the square root of r^2
