Solve!<br><br> 1. p/5 = -2<br> 2. y/-3 = 33<br> 3. -7n = 35

Kara’s car used 1/16 gallons of gas to drive 1/8 of a mile at this rate how many miles can Kara’s car drive using one gallon of

marissa [1.9K]

Answer is 2 miles
Hope this helps

8 0

2 years ago

Use a drawing of counters to show 5 and then +7

Rama09 [41]

red red red red red yellow yellow yellow yellow yellow yellow

hope this helps :)

3 0

2 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

A 6-pound bag of birdseeds cost $4.92. What is the unit price?

Sergeu [11.5K]

I think you would have to multiply $4.92 and 6... if so the answer would be $29.52 for the unit price.

7 0

3 years ago

Jennifer jogged over to Collin's house last Saturday. She first ran from her house to the lake, which took her 15 minutes. She t

Alexus [3.1K]

Just work the problem in reverse.
1:14pm - 24 minutes would be 12:50pm.
12:50pm - 15 minutes would be 12:35pm.
Jennifer left her house at 12:35pm.

5 0

3 years ago

Solve! 1. p/5 = -2 2. y/-3 = 33 3. -7n = 35