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3 years ago

HEY PLEASE THANK YOU

1 answer:

5 0

Radon hope this helps.

original answer was monoxide which is incorrect and dioxide is incorrect and it is not hydrogen meaning it has to be radon.

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What is the total number of atoms in the formula<br> Ca(ClO3)2?

Contact [7]

Answer:

9 atoms

Explanation:

Ca=1

Cl=2

O=6

add them all

5 0

3 years ago

Read 2 more answers

__Mg + __Fe2O3 -> __MgO + __Fe

Anika [276]

Answer:

Your correct answer is A. 1,2,1,2

Explanation:

Please mark brainliest!

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3 years ago

Which of the following would contain 48 electrons?

Helga [31]

The answer is cadmium its got 48 electrons which is y its number 48 on the period table

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3 years ago

A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct

arsen [322]

Answer:

Plausible structure has been given below

Explanation:

Molar mass of $CO_{2}$ is 44 g/mol and molar mass of $H_{2}O$ is 18 g/mol
Number of mole = (mass/molar mass)

4.04 g of $CO_{2}$ = $\frac{4.04}{44}moles$ $CO_{2}$ = 0.0918 moles of $CO_{2}$

1 mol of $CO_{2}$ contains 1 mol of C atom

So, 0.0918 moles of $CO_{2}$ contains 0.0918 moles of C atom

1.24 g of $H_{2}O$ = $\frac{1.24}{18}moles$ $H_{2}O$ = 0.0689 moles of $H_{2}O$

1 mol of $H_{2}O$ contain 2 moles of H atom

So, 0.0689 moles of $H_{2}O$ contain $(2\times 0.0689)moles$ of $H_{2}O$ or 0.138 moles of $H_{2}O$

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is $C_{2}H_{3}$

So, molecular formula of one of it's analog is $C_{4}H_{6}$

Plausible structure of $C_{4}H_{6}$ has been given below.

4 0

3 years ago

Plz help (it’s a picture)

Feliz [49]

Umm I’ll figure it out rn! Will come back in 1 min

7 0

3 years ago