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Vedmedyk [2.9K]
3 years ago
9

Aqueous solutions of isopropyl alcohol are commonly sold as rubbing alcohol. The boiling point of isopropyl alcohol is 82.4 °C.

It evaporates readily from the surface of the skin. Ethylene glycol (CH2OHCH2OH) is sold as antifreeze/antiboil. The boiling point of ethylene glycol is 198 °C. The molecular masses of isopropyl alcohol and ethylene glycol are similar. Provide an explanation for the observed difference in their boiling points.
Chemistry
1 answer:
Monica [59]3 years ago
8 0

Answer:

This is due to more hydrogen bonding in ethylene glycol than it is in isopropyl alcohol

Explanation:

The boiling point of isopropyl alcohol is 82.4 °C it contains only a single OH group, hence intermolecular hydrogen bonding is solely responsible for it's boiling point, whereas Ethylene glycol (CH2OHCH2OH) contains 2-OH group and both intermolecular and intramolecular hydrogen bonding are responsible for the higher boiling point of ethylene glycol at 198 °C.

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A quantitative observation must be a measurement of some sort. (Something including numbers). Qualitative, on the other hand, is when you are using words to describe what has happened.
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3 years ago
In a solution, the solvent In a solution, the solvent can be a liquid or gas. A. is the substance present in the smallest concen
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Answer:

Can either be a solid, a liquid or a gas

Explanation:

A solvent can either be a solid, liquid or a gas. It is the carrier medium in a solution. It is the one in which the solute is dissolved.

Although quite unusual, a solvent might also be a solid. An important application of this can be seen in the production of alloys. Alloys are mixture of metals. To produce let’s say an alloy containing just two metals, the use of a solid solvent is needed. Here, one of the two metals is known as the base metal. It is this base metal that will serve as the carrier medium for the other metal

6 0
3 years ago
Would the size of an item affect whether or not it is flammable?
pochemuha

Answer:

No! It only depends on the chemicals in or on the object.

Explanation:

Hope this helped! :)

5 0
3 years ago
Calculate the amount of heat needed to boil 120.g of acetic acid (HCH3CO2), beginning from a temperature of 16.7°C.
evablogger [386]

Answer:

The total amount of heat needed = 72.2116  kJ

Explanation:

Given that ;

the mass of acetic acid = 120.0 g

The initial temperature T_1 = 16.7 °C  = (16.7 + 273.15 ) K = 298.85 K

The standard molar mass of acetic acid = 60.052  g/mol

Thus ; we can determine the number of moles of acetic acid;

number of moles of acetic acid = mass of acetic acid/ molar mass of acetic acid

number of moles of acetic acid = 120.0 g/ 60.052 g/mol

number of moles of acetic acid =  1.998 moles

For acetic acid:

The standard boiling point  T_2 = 118.1 °C = ( 118.1 + 273.15 ) K = 391.25 K

The enthalpy of vaporization of acetic acid \Delta H_{vap} = 23.7 kJ/mol

The heat capacity of acetic acid   c = 2.043  J/g.K

The change in temperature Δ T = T_2 - T_1

Δ T = (391.25 - 289.85)K

Δ T = 101.4 K

The amount of heat needed to bring the liquid acetic acid at 16.7°C to its boiling point is ;

q = mcΔT

From our values above;

q = 120 g ×  2.043  J/g.K × 101.4 K

q = 24859.2  J

q = 24859 /1000 kJ

q = 24.859 kJ

we have earlier calculated our number of moles o f acetic acid to be 1.998 moles;

Thus;

The needed amount of heat = \Delta_{vap} *numbers \ of  \ moles

The needed amount of heat = 23.7 \ kJ/mol * 1.998 \ moles

The needed amount of heat = 47.3526 kJ

Hence;

The total amount of heat needed = 24.859 kJ + 47.3526 kJ

The total amount of heat needed = 72.2116  kJ

4 0
3 years ago
A solution has a pH of 2.5. what is the H+
romanna [79]

<u>Answer: </u>The concentration of H^+ in the solution is 3.16\times 10^{-3}M

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.

pH=-\log [H^+]      .....(1)

We are given:

pH of solution = 2.5

Putting values in equation 1, we get:

2.5=-\log [H^+]

[H^+]=10^{-2.5}

[H^+]=3.16\times 10^{-3}M

Hence, the concentration of H^+ in the solution is 3.16\times 10^{-3}M

4 0
3 years ago
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