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Sergio [31]
4 years ago
13

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app

roximately 1.3%/year, find a function Q that expresses the world population (in billions) as a function of time t (in years). (Let t = 0 represent 1980 where t is years since 1980.)
What does Q(t) = and what will the world population be at the beginning of 2019 ?
Mathematics
1 answer:
AfilCa [17]4 years ago
6 0

Answer:

Q(t) = 4.5(1.013)^{t}

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that Q(0) = 4.5, r = 0.013

So

Q(t) = Q(0)(1+r)^{t}

Q(t) = 4.5(1.013)^{t}

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

Q(t) = 4.5(1.013)^{t}

Q(39) = 4.5(1.013)^{39} = 7.45

The world population at the beginning of 2019 will be of 7.45 billion people.

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likoan [24]
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3 years ago
Hi good morning can you please help me Write two polynomials whose difference is 6x+3
vaieri [72.5K]

Answer:

9x+8 and 3x+5.

Explanation:

Let the first polynomial = 9x + 8

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\begin{gathered} 9x-a=6x \\ a=9x-6x \\ a=3x \end{gathered}

Similarly:

\begin{gathered} 8-b=3 \\ b=8-3 \\ b=5 \end{gathered}

Thus, the second polynomial = 3x+5

Therefore, the two polynomials whose difference is 6x+3 are 9x+8 and 3x+5.

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1 year ago
A sphere is inscribed in a cube, and the cube has a surface area of 24 square meters. A second cube is then inscribed within the
snow_tiger [21]

Check the picture below, I'll be referring to the material in the picture.

we know the outer cube has a surface area of 24, we also know is a cube, so it has 6 equal sides which are squares each, let's say the side of one of those squares in the cube is say of length "s", so the area of one square will just be  s², and for 6 squares that'll be an area of 6s², that is the area of the outer cube, which we know is 24.

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now, we know the sphere is inscribed in the outer cube, so it's touching its edges, like you see in the picture in blue, so if we get a cross-section of the whole lot, we'd get the picture to the right of blue cube in the picture, an outer cube with a side of 2, and therefore an sphere with a diameter of 2, and thus a radius of 1, as you can see in the red triangle.

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\stackrel{\textit{half a side}}{\cfrac{1}{\sqrt{2}}}\qquad \stackrel{\textit{a full side}}{\cfrac{1}{\sqrt{2}}+\cfrac{1}{\sqrt{2}}}\implies \cfrac{2}{\sqrt{2}}\implies \cfrac{2\sqrt{2}}{\sqrt{2}\sqrt{2}}\implies \cfrac{2\sqrt{2}}{2}\implies \sqrt{2}

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Total billed amount of fridge including VAT = $480

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Let us set an equation to find the value of x.

<h3>x+0.20x = 480.</h3>

1.20x = 480.

Dividing both sides by 1.20, we get

1.20x/1.20 = 480/1.20

x= 400.

<h3>Therefore, $ 400 is the price of the fridge before the VAT added.</h3>
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