Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
Answer:
1,041.9feet
Step-by-step explanation:
Given the height of the rocket expressed as
y = -16x² + 245x + 104
At maximum height, dy/dx = 0
dy/dx = -32x+245
0 = -32x+245
32x = 245
x = 245/32
x = 7.65625
Get the maximum height
Recall that;
y = -16x² + 245x + 104
Substitute the value of x;
y = -16(7.65625)² + 245(7.65625) + 104
y = -937.890625 + 1,875.78125 + 104
y = 1,041.890625feet
Hcne the maximum height to the nearest foot is 1,041.9feet
i agree with martin because i added 700+490+17 and got 1,207
Answer:
5
Step-by-step explanation:
Just multiply 5/7 by 7 since his dog retrieved 5/7 out of the 7 ducks he shot.