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lana66690 [7]
2 years ago
11

A retailer has determined that the cost C of

Mathematics
1 answer:
adelina 88 [10]2 years ago
7 0
A. The expression given in the question is

c = 6x + (900000/x)
c = (6x^ +900000)/x
I hope that this is the expression that you were looking for.

b. When x = 240, then

c = [6 * (240)^2 + 900000]/ 240
   = (6 * 57600) + 900000/240
   = (345600 + 900000)/240
   = 5190

From the above deduction, it can be concluded that the cost of ordering and storing is 5190. I hope the procedure is clear enough for you to understand.
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4x²-24x-36 = 0<br>Help please......​
GrogVix [38]

Explanation:

Given equation is 4x²-24x-36 = 0

⇛ 4(x²-6x-9) = 0

⇛ x²-6x-9 = 0

⇛ x²-2(x)(3) = 9

On adding 3² both sides then

⇛ x²-2(3)x)+3² = 9+9

⇛ (x-3)² = 18

⇛ (x-3) = ±√18

⇛ x-3 = ±√(2×9)

⇛ x-3 = ±3√2

⇛ x = 3±3√2

⇛ x = 3+3√2 or 3-3√2

4 0
2 years ago
What is the solution of the system when just looking at the equations? No Graph!
Kaylis [27]

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

y = 5x + 2 and y = 5x – 8

m = 5                 m = 5

b = 2                  b = -8

When comparing equations:

1. Put in <u>slope-intercept</u> form.

2. Compare the <u>slopes and the y-intercepts</u>!

This system has <u>no solution.</u>

Because we have the same slopes and different y-intercepts.

If the slopes are the same and the y-intercepts are the same, then that system has infinitely many solutions.

If the slopes are different, then that system has one solution.

6 0
3 years ago
The Kappa Iota Sigma Fraternity polled its members on the weekend party theme. The vote was as follows: six for toga, four for h
Nadusha1986 [10]

Answer:

<u><em>note:</em></u>

<u><em>solution is attached</em></u>

3 0
3 years ago
Find parametric equations for the line through point P(-4,5,2) in the direction of the vector (-6,6,-5)
tigry1 [53]

The vector <em>v</em> (-6, 6, -5) points in the direction of itself, so we start there.

We can capture all points on the line through the origin and the point (-6, 6, -5) by scaling <em>v</em> by an arbitrary real number <em>t</em>.

The line through point <em>P</em> and pointing in the same direction as <em>v</em> is parallel to the other line that passes through the origin. Then the line we want can be obtained by translating the line through the origin by a vector <em>p</em> that points to (-4, 5, 2), so the vector equation for this line is

<em>r </em>(<em>t </em>) = <em>p</em> + <em>t v</em>

<em>r </em>(<em>t </em>) = (-4, 5, 2) + <em>t</em> (-6, 6, -5)

<em>r </em>(<em>t </em>) = (-4 - 6<em>t</em>, 5 + 6<em>t</em>, 2 - 5<em>t</em> )

To get the parametric equations, simply take out the components:

<em>x</em> (<em>t</em> ) = -4 - 6<em>t</em>

<em>y </em>(<em>t</em> ) = 5 + 6<em>t</em>

<em>z</em> (<em>t</em> ) = 2 - 5<em>t</em>

4 0
2 years ago
Can someone please help me on this
Naddik [55]
12345678911111111111
7 0
3 years ago
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