There are 4 aces in a deck of 52 cards. the odds of drawing one is 1/13. the probability of doing it again is still 1/13. the odds of doing it twice, as described, is then 1/13 * 1/13, or (1/13)², or 1/169 option A
The answer is y = -8x - 20. If you were to use y = 8x - 20 then you'd get 4 = -44, which, obviously, is not true. To fix it all you need to do is add a negative sign in front of the 8. y = -8x - 20.
Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,

Substituting the values we get

The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
It’s 456 well done great job i am not sure really